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TommiH69
Expert
Germany
54 Posts |
 Posted - 05 Apr 2012 : 09:52:49
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Hallo,
I only have a short problem. I put a dummy-pic (A) on a page and a second (B) on the right side of the page. I hide B and I put 2 events in A. (onClick -> show B - and - onMouseIut -> hide B)
That works fine - BUT - B will be shown at B-POSITION, and not at A-position.
I know this will work, because I did it in the past, but I don't know it actually :(
Tommi
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Edited by - TommiH69 on 05 Apr 2012 11:34:12 |
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s.dav
Site Admin
Italy
3364 Posts |
Posted - 06 Apr 2012 : 13:52:19
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| You haven't to use the "Show"/"Hide" action but "SetImage" |
Regards, Davide |
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TommiH69
Expert
Germany
54 Posts |
Posted - 04 Mar 2013 : 16:38:06
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Hm, yes, this will work fine - but ;) how can I HIDE B (reactivate pic A) after onMouseOut ?
SetImage A on place A will not work
hide B will not work
show A will not work too
Can somebody give me the right way to reactivate A?
Tommi
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s.dav
Site Admin
Italy
3364 Posts |
Posted - 05 Mar 2013 : 15:28:48
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| You need to place two dummy hidden pics on your page and use the SetImage to exchange them :-) |
Regards, Davide |
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TommiH69
Expert
Germany
54 Posts |
Posted - 06 Mar 2013 : 16:36:04
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Okay, that works, thx!
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Topic |
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Forgotton procedure for pic-showing
